8^x=(1/32)^(x-2)

Solution for 8^x=(1/32)^(x-2) equation:

8^x=(1/32)^(x-2)

We move all terms to the left:

8^x-((1/32)^(x-2))=0


Domain of the equation: 32)^(x-2))!=0

x∈R


We add all the numbers together, and all the variables

8^x-((+1/32)^(x-2))=0

We multiply all the terms by the denominator


8^x*32)^(x+1-2))-((=0

We add all the numbers together, and all the variables

8^x*32)^(x-1))-((=0

We add all the numbers together, and all the variables

8^x*32)^(x=0

Wy multiply elements

256x^2=0

a = 256; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·256·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{512}=0$